a pulse is generated at one end of the slinky of lenght 10 m .The pulse returns back to its point of generation in 10 seconds.what is the velocity of the pulse produced by the slinky?
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lamda=10 m
time =10 second
f=1/t=1/10= 0.1hz
v=f×lamda
=0.1 × 10
v= 1m/s
1m/s is the velocity of the pulse produced by the slinly
time =10 second
f=1/t=1/10= 0.1hz
v=f×lamda
=0.1 × 10
v= 1m/s
1m/s is the velocity of the pulse produced by the slinly
raghu63:
i think the answer is 2 as it travelled 20 m in 10 sec. am i right.
but u have given that ,10m in 10sec .if I am wrong then sorry
till my understanding goes, you cant use lamda and frequency relation in the production of pulse. Its used to know the velocity of sound.
Answered by
2
Total distance travelled by the pulse=(10 x 2)m=20 m
Total time taken by it=10 secs
Velocity =total distance/total time=20m/10 secs=2 m/s.
Total time taken by it=10 secs
Velocity =total distance/total time=20m/10 secs=2 m/s.
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