a pulse was created in a stretched string of 5m it was observed that the pulse returned after reflection at the point of creation 5 times in 10 seconds calculate the speed...
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Hey buddy,
◆ Answer-
v = 5 m/s
◆ Explaination-
# Given-
n = 5
l = 5 m
t = 10 s
# Solution-
In each cycle, distance travelled is 2l.
i.e. 2×5 = 10 m.
Total distance traveled in 5 cycles,
s = 5×10 = 50 m
Velocity is calculated by-
Velocity = distance / time
v = s / t
v = 50 / 10
v = 5 m/s.
Therefore, speed of wave is 5 m/s.
Hope it helps...
◆ Answer-
v = 5 m/s
◆ Explaination-
# Given-
n = 5
l = 5 m
t = 10 s
# Solution-
In each cycle, distance travelled is 2l.
i.e. 2×5 = 10 m.
Total distance traveled in 5 cycles,
s = 5×10 = 50 m
Velocity is calculated by-
Velocity = distance / time
v = s / t
v = 50 / 10
v = 5 m/s.
Therefore, speed of wave is 5 m/s.
Hope it helps...
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