Question

A pump can be operated both for filling a tank and for emptying it. The capacity of the tank is 2400 m3. The emptying capacity of the pump is 10m3 per minute higher than its filling capacity. Consequently, the pump needs 8 minutes less to empty the tank than to fill it. Find the filling capacity of the pump.

Answer 1

Answer:

Step-by-step explanation:

Let the filling capacity of the pump be x m3/min.

Then, emptying capacity of the pump=(x+10)m3/min.

so,2400x−2400x+10=8 ⇔x2+10x−3000=0

⇒(x−50)+(x+60)=0 ⇔x=50

Hope it helps you...

Answer 2

SOLUTION

Given,

Capacity of tank=2400m³

Emptying Capacity of the pump=10m³/min=1/6m³/s

Let the time taken to fill the tank be x

Therefore,

Time taken to empty tank= (x-480)s

A/Q

Volume=Time taken to empty ×Emptying Capacity

2400=(x-480)(1/6)

2400×6=x-480

x=14400+480

x=14880

Therefore filling Capacity of tank= Capacity of tank/Time

=2400/14880

=10/62=5/31m³/s

or 5m³/31s