a pump can take out 7200 kg of water per hrs from a 100 m deep well . calculate the power of the pumpa assuming that its efficiency is 50% (g=10m/s2)
Answers
Answered by
17
Explanation:
mgh/t = 7200×10×100/3600 = 2000 W
efficiency = output power / input power
input power = output power/d = 2000×100/50 =4kw
Answered by
4
Answer:4kw or 4000watt
Explanation:
Given below
Attachments:
Similar questions