Question

A pump delivers 1000 L of water in a tank of height of 15m in 120 sec. Calculate the work done by the pump and its power.

Answer 1

Let us consider the density of water to be 1g/litre. Therefore the mass of the water pumped is 1000g = 1kg
work done = mgh = 1*10*15 = 150 J
power = work done / time = 150/120 = 1.25 Watt

Answer 2

Here's your answer!!

Answer:

Given:-

h=15m

Mass of water=1000 L ×1kg/ L =1000kg

SO,

work done by the pump is equal the potential energy =mgh

=1000×10×15

=150 KJ

Power = work/ Time

= 150×10³ J / 120s

= 1.25 Kw

Therefore,

Work done by the pump = 150 J

The power of the pump = 1.25 Kw

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