Physics, asked by SidharthSajith, 7 months ago

A pump draws 1000kg of water per minute from a well 12m deep. find the power of the pump​ in HP unit would be very nearly equal to....................(given g=10m/s²)


a)2.0 b)2.3 c)2.63 d)2.5

plz help urgent

Answers

Answered by LoverLoser
13

\small{\underline{\sf{\orange{Given:\rightarrow}}}}

  • Mass of the Water pumped per minutes = 1000 kg.
  • Height of the well = 12 m.

\small{\underline{\sf{\red{Formula\ used:\rightarrow}}}}

\boxed{\sf{Power = \dfrac{Work}{Time} }}

\small{\underline{\sf{\blue{Solution:\rightarrow}}}}

Energy used in pumping the water = Change in Potential energy

= mgh - 0

=  1000 × 10 × 12 = 120000 J.

\sf{Power = \dfrac{Work}{Time}}\\\sf{Power= \dfrac{120000}{60}}\\\sf{Power= 2000 W}

To Convert it into Horse Power,

\sf{\therefore 1 Hp = 746 W}

\sf{ 2000 W = \dfrac{2000}{746} Hp. = 2.68 Hp} {app.}

c)2.63 is the correct option

______________________

Answered by gsiddhant041
1

Explanation:

Given:→

Mass of the Water pumped per minutes = 1000 kg.

Height of the well = 12 m.

\small{\underline{\sf{\red{Formula\ used:\rightarrow}}}}

Formula used:→

\boxed{\sf{Power = \dfrac{Work}{Time} }}

Power=

Time

Work

\small{\underline{\sf{\blue{Solution:\rightarrow}}}}

Solution:→

Energy used in pumping the water = Change in Potential energy

= mgh - 0

= 1000 × 10 × 12 = 120000 J.

$$\begin{lgathered}\sf{Power = \dfrac{Work}{Time}}\\\sf{Power= \dfrac{120000}{60}}\\\sf{Power= 2000 W}\end{lgathered}$$

To Convert it into Horse Power,

$$\sf{\therefore 1 Hp = 746 W}$$

$$\sf{ 2000 W = \dfrac{2000}{746} Hp. = 2.68 Hp}$$ {app.}

c)2.63 is the correct option

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