Physics, asked by krajasekhar598, 1 year ago

a pump id required to lift 600kg of water per minute from a well of depth 25 meters deep and to eject it with a speed of 50 meter per second calvary the power required to perform the above task

Answers

Answered by wwwfireemblem1996gam
0

600kg=6000N

Power=Work÷Time

(6000×25)÷60

=150000÷60

=2500 watts


wwwfireemblem1996gam: don't know if the answer is correct or not because you just asked for power
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