Question

A pump is required to lift 600 kg of water from well 25m deep to

Answer 1

Explanation:

Give complete question Mr Kumar.

Answer 2

HEYA MATE HERE U GO.

Mass of water lifted (m) = 600kg

depth of well (h) = 25 m

work done to lift water (w1) = mgj = 600× 9.8 × 25 = 147000J

speed of water (v) = 50ms^-1

Mass of water (m) = 600kg

work done to given K.E to water , w2 = 1/2 mv^2 = 1/2 × 600 × 2500 = 750000 J

Total work done W = W1 + W 2 = 147000+ 750000= 897000J

Time taken (t) = 1 minute = 60s.

Therefore Power required = workdone /time = 89700/60 = 14950 w = 14.95 kW.