Question

A pump is required to lift 600 kg of water per minute from a well 25 m deep and to eject it with a speed of 50 m s⁻¹. Calculate the power required to perform the about task?

Answer 1

Hii dear,

# Answer- 15 kW

# Explaination-
# Given-
v = 50 m/s
m/t = 600 kg/min = 10 kg/s
h = 25 m

# Solution-
Here, Gravitational P.E.
PE/t = 10 × 10 × 25
PE/t = 2500 J/s

Also, kinetic energy
KE/t = 1/2 mv^2
KE/t = 0.5 × 10 × (50)^2
KE/t = 12500 J/s

Power = Work done/time
Power = (PE + KE) / t
Power = 2500 + 12500
Power = 15000 Watt.

Power required is 15 kW.

Hope that is useful..

Answer 2

Answer:

Refer to the attachment,,

h = 25m

v = 50m/s

power = ??

= 15kw