A pump is required to lift 800kg of water per minute from a 10m deep well and eject it with a speed of 20ms-1. what will be the power of the pump required ?
Answers
Answered by
52
M=800 kg. T=60s
H=10m
V=20m/s
Power=w/t
P=mgh+1/2mv^2/t
=800*10*10+1/2*800*20^2
=240000/60
=4000 w
H=10m
V=20m/s
Power=w/t
P=mgh+1/2mv^2/t
=800*10*10+1/2*800*20^2
=240000/60
=4000 w
Answered by
5
M=800 kg. T=60s
H=10m
V=20m/s
Power=w/t
P=mgh+1/2mv^2/t
=800*10*10+1/2*800*20^2
=240000/60
=4000 w
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