Question

A pump is rewuired to lift 600 kg of water per minute frim a well 25m deep and to eject it with a speed of 50 ms- 1. calculatethe power required to perform the above task

Answer 1

600kg water/ min = 10kg water/ sec I'll take g to be 10 

GPE per second = 10*10*25 = 2500 W 

KE per second = 1/2(10)(50)^2 = 12500 

Total power = 15000 W

Answer 2

Answer:

The power required is 15000 kW.

Explanation:

Given : A pump is required to lift 600 kg of water per minute firm a well 25 m deep and to eject it with a speed of 50 m/s.

To find : Calculate the power required to perform the above task ?

Solution :

The velocity is v=50 m/s

The mass per minute is m=600 kg/min

In kg/s the mass is m=$\frac{600}{60}=10kg/s$

The height of well is h=25 m.

We know,

Power is the sum of kinetic energy and potential energy.

$P=P.E+K.E$

$P=mgh+\frac{1}{2}mv^2$

Substitute the values,

$P=10\times 10\times 25+\frac{1}{2}\times 10\times 50^2$

$P=2500+12500$

$P=15000 \text{ Watt}$

or $P=15000 \text{ killoWatt}$

Therefore, The power required is 15000 kW.