Question

a pump is used to lift 500 kg of water from a depth gets if 80m in 10 second ,calculate the work done by the pump, the power at which the pump works and the power rating of the pump if its efficiency is 40%(taking g=10ms-1)

Answer 1

work done by pump = mgh
= 500×10×80
= 400000 J
power = 400000/10 = 40000watt
efficient power = 40000 × 40/100
= 16000watt.