A pump is used to lift 500 Kg of water from a depth of 30m to height of 50m in 10s. Calculate the : (i) Work done by the pump and (ii) Power rating of the pump if its efficiency is 40%. Take g = 10 m/s2.
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Answer:
i/ workdone w = F x d
w= 500 x (50-30)
w= 500 x 20
w=10000 J
ii/ power = workdone/time
p = 10000)/10
P1 =1000W
effience e =p2/p1
p2 = 0.4 x1000
power output p2 =400w
Explanation:
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