Question

A pump is used to lift 500kg of water from a depth of 80m in10s is calculate the power rating at a pump if efficindly is 40% . take g=10m/s2
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Answer 1

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Work = Mass × Displacement

Work = 500 × 80

Work = 400000 J

We know,

Power(P) = Energy/Time

Power(P) = 500 × 10 × 80/10

Power(P) = 40000 W or 40 kW

According to question, we need to find power rating.

So, we know

Power rating = Useful power/ Efficiency 

Power rating = 40x100/40

Power rating = 100 kW