Question

A pump is used to lift 500kg of water from a depth of 80m in 10s. Calculate: <br />
(i)the power rating of the pump it its efficiency is 40%. (Take g=10ms².)

Answer 1

I think we need to calculate the work done
so,

force=500*10N =5000N

S=80 m

t=10s

W=F*S=5000*80=400000J

P=W/t=400000/10=40000W

poweroutput/power input=efficiency

40000/power input=40/100

power input=100000W