A pump is used to lift 500kg of water from a depth of 80m in 10s. Calculate: <br />
(i)the power rating of the pump it its efficiency is 40%. (Take g=10ms².)
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I think we need to calculate the work done
so,
force=500*10N =5000N
S=80 m
t=10s
W=F*S=5000*80=400000J
P=W/t=400000/10=40000W
poweroutput/power input=efficiency
40000/power input=40/100
power input=100000W
so,
force=500*10N =5000N
S=80 m
t=10s
W=F*S=5000*80=400000J
P=W/t=400000/10=40000W
poweroutput/power input=efficiency
40000/power input=40/100
power input=100000W
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