a pump lifts 100kg of water to a tank 35 m above the ground . if it takes 20 s to lift the water , calculate the power of the pump .( g = 10 m/s2)
Answers
Answer:
1,750 W
Explanation:
Given:
- Mass of water (m) = 100 kg
- Height (h) = 35 m
- Time (t) = 20 sec
- Acceleration due to gravity (g) = 10 m/s²
To find:
- Power of pump (P) = ?
Solution:
We remember that, Power = (Work or energy) ÷ Time.
We also remembers that,
Work done = Fs
Where, F = force applied in Newton
s = Height or distance covered in meters.
We also know that, Force = Weight of an object = mg
Where, m = mass of object
g = acceleration due to body.
________________________________
Let's first find the force applied then we will find the work done and then power, that's our approach !
⇒ F = mg
⇒ F = 100 × 10
⇒ F = 1000 N
So, the force applied = 1000 Newton.
⇒ Work done = Force × Displacement covered
⇒ Work done = 1000 × 35
⇒ Work done = 35,000 J
Thus, the work done = 35,000 Joules.
Now, the final step.
⇒ Power = Work done ÷ Time
⇒ Power = 35,000 ÷ 20
⇒ Power = 1750 W
Therefore, the power of pump = 1,750 Watt.
We remember that, Power = (Work or energy) ÷ Time.
Work done = Fs
Where, F = force applied in Newton
s = Height or distance covered in meters.
We also know that, Force = Weight of an object = mg
Where, m = mass of object
g = acceleration due to body.
________________________________
Let's first find the force applied then we will find the work done and then power, that's our approach !
⇒ F = mg
⇒ F = 100 × 10
⇒ F = 1000 N
⇒ Work done = Force × Displacement covered
⇒ Work done = 1000 × 35
⇒ Work done = 35,000 J
Now, the final step.
⇒ Power = Work done ÷ Time
⇒ Power = 35,000 ÷ 20
⇒ Power = 1750 W