A pump pumps 54 Litres of water to a height of 100m. If the efficiency of the pump is 80%, What is its power?
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3.33kW
Explanation:
L = 54l
h=100m,
g=10m/s2,
η=80%
output power, P0=mghl=100×10×105
Input power Pi=?
As η=PoPi∴Pi=Poη=260/100=3.33kW
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