Physics, asked by rameshsuthari9848, 2 months ago


A pump required to list 1000 kg of water per minute from a well 20 m deep and eject it at a rate of
20m/s
How much work done in lifting water
[
a) 9.8 x 10$ J min! b) 19.6 x 105 J min! c) 27.4 x 105 J min! d) 39.4 x 10$ Jms!
How much work done in giving it K.E.
1
a) 2 x 10 min b) 3 x 10 J min c) 1.5 x 10 J min d) 2.5 x 10% J min-
What Horse power (HP) engine required for the pupose of lifting water
a) 6.6 x 102 HP
b) 8.85 HP
c) 5.5 x 10 HP d) 9.2 HP​

Answers

Answered by pranjalbhr2008
2

Answer:

pls mark me brainlest

answer = 3.25

Explanation:

Given,

m=1000kg

t=1min=60sec

h=10m

v=10m/s

g=10m/s  

2

 

Power, P=  

t

mgh+  

2

1

​  

mv  

2

 

​  

 

P=  

60

1000×10×10+  

2

1

​  

×1000×10×10

​  

 

P=  

60

100000+50000

​  

=  

60

150000

​  

=2500W

As we know that, 1horse−power=746Watt

1W=  

746

1

​  

horse−power

2500W=  

746

2500

​  

=3.25HP

The correct option is A.

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