Question

A pure H2so4 (98% by weight) solution has a specific gravity of 1.8 . the normality of the h2so4 is :
a. 9N
b. 18N
c. 72N
d. 36N​

Answer 1

Explanation:

Density of solution = 1.8g/cm^3= 1800g/ L

Weight of h2so4 = (98×1800)g/100= 1764 g

no .of Equivalent of h2so4 = 1764g/(mass of one equivalent )

= 1764/ 49 = 36

Required normality = (no of equivalents)/volume of solution = 36 N

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Answer 2

Answer:

Option D is the required answer of your question

36 N is the answer of the required Solution

Explanation:

We have , Density of solution = 1.8 g /cm^3= 1800 g/ L

We can also have , Weight of h2so4 = ( 98 ×1800 ) g / 100= 1764 g

This implies that ,

no .of Equivalent of h2so4 = 1764g/(mass of one equivalent )

= 1764/ 49 = 36

Hence , the final solution

Required normality = (no of equivalents)/volume of solution = 36 N