Question

A pure inductive coil allow a current of 10 amp to flow from 230 volt , 50 hertz find I) inductive reactance 2) inductance of the coil 3) power consumed. ​

Answer 1

Explanation:

Reactance =ωL

=2πfL

=2π×50×0.5

=157Ω

Answer 2

Answer:

Here, L = 10 mH = 10 * 10 ^-3 H = 10 ^-2 H

frequency = 100 Hz

using, Xl = Lω = L * 2*π*frequency

∴ Xl = 10^-2 * 2 * 3.14 * 100

                    = 6.28 ohm

hope it helps