Question

. A pure tall plant bearing red colour flowers was
crossed with a pure dwarf plant with white flowers.
(i) What would be the nature of offsprings in the F1
generation ?
(ii) If the offsprings of the Fı generation are self-
pollinated, what would be the ratio of red flowers
to white flowers in the F2 generation ?
(iii) What can you infer from the ratio obtained in
(ii) ? Which law does it illustrate ?​

Answer 1

Answer:

• The F-1 generation is heterozygous tall
• 1:2:1 genotypic, phenotypic 3:1 , 3-red flowers and 1 white flower
• red flower is dominant , white is recessive
• Here law of inheritance occurs.....

Answer 2

Answer:

i) The offspring in F1 generation would be heterozygous.

ii) In case of Monohybrid cross (as they mentioned only colour of flowers) the genotypic ration should be 1:2:1 ( RR:Rr:rr)

and phenotypic ratio should be 3:1 (Red:white)

But as per main question's condition it should be : 1:2:1:2:4:2:1:2:1 (RRYY 1: RRYy 2: RRyy 1: RrYY 2: RrYy 4: Rryy 2: rrYY 1: rrYy 2: rryy 1) and phenotype ratio should be 9:3:3:1 (Tall&Red: Tall&white:Dwarf&Red:Dwarf&white)

iii) The ration obtained in b illustrate Law of Independent assortment.( for monohybrid cross)