A PURSE CONTAIN 25PAISE AND 50PAISE COINS THE NUMBER OF FOEMER COINS IS THREE TIMES THE LATTER IF THE TOTAL MONEY IN THE PURSE IS RS50 FIND THE NUMBER OF COINS OF EACH TYPE
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no. of 25 paisa coins = 3x
no. of 50 paisa coins = x
money of 25 paisa coins = 25× 3x = 75x
money of 50 coins = 50× x = 50x
total money = ₹50 = 5000 paisa
75x+50x=5000
125x=5000
x = 40
no. of 25 paisa coins is 120
no. of 50 paisa coins is 40
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no. of 50 paisa coins = x
money of 25 paisa coins = 25× 3x = 75x
money of 50 coins = 50× x = 50x
total money = ₹50 = 5000 paisa
75x+50x=5000
125x=5000
x = 40
no. of 25 paisa coins is 120
no. of 50 paisa coins is 40
please follow me
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