A PURSE CONTAIN RS 550IN NOTE OF DENOMINATION OF RS 10 AND RS 50. IF THE NUMBER OF RS 50 NOTED IS ONE LESS THAN OF RS 10 NOTES ,THEN FIND THE NUMBER OF RS 50 NOTES.
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5
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Step-by-step explanation:
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Here is your Answer
_____________________________
Let the number of 10Rs be X
then
number of 50rs be (x-1)
so
10 rs note = 10x
50 Rs note = 50(x-1)
=50x-50
Now equation
10x +50x -50 = 550
60x -50 = 550
60x = 550+50
X = 600/60
X = 10
Thus the 10 rs note are 10
&
50Rs note (10-1) = 9
50Rs note =9
10Rs note = 10
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Answered by
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let no.of 10.Rs. notes be X and 50rs.notes.be x-1.value=10 (x)+50(x-1)=550
10x+50x-50=550
60x-50=550
60x=600
x=10
no.of 50rs.notes =10-1=9
no.of 10.Rs notes=10.
hope the answer is right
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10x+50x-50=550
60x-50=550
60x=600
x=10
no.of 50rs.notes =10-1=9
no.of 10.Rs notes=10.
hope the answer is right
pls.follow me
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