A purse contain rupees 10,800 in term of 50 paise,2 rupees and 5rupees coin in the ratio 2:3:4. Find the number of each type of coins
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let
n included in the both ratio
then
ratio number = 2n , 3n , 4n
sum of the ratio = 2n+ 3n + 4n
= 9n
now
9n = 10800
n = 10800 / 9
= 1200
isaliye 50 Paise coin = 2400
2 rupee coin = 3600
5 rupee coin = 4800
n included in the both ratio
then
ratio number = 2n , 3n , 4n
sum of the ratio = 2n+ 3n + 4n
= 9n
now
9n = 10800
n = 10800 / 9
= 1200
isaliye 50 Paise coin = 2400
2 rupee coin = 3600
5 rupee coin = 4800
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