A purse contains 25 paisa and 10 paisa coins. The total amount in the purse is Rs 8.25. The number of 25 paisa coins is one third of the number of 10 paisa coins. Form linear equations to represent this situation
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Answered by
1
Answer:
60
Step-by-step explanation:
Let x be the number of 25-paise coins and y be the number of 10-paise coins.
0.25x+0.10y=8.25
4
1
x+
100
1
y=8.25 ....(1)
and x=
3
1
y ....(2)
Substituting eq(2) in eq(1), we get
12
1
y+
100
1
y=
100
825
⇒
1200
112
y=
100
825
⇒y=
112
825×12
⇒y=45
∴x=15
Hence, the total number of coins =15+45=60.
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