Question

a purse contains $3.75 in 5 cents and 20 cent coins. there are 33 coins altogether. how many of each coin type of coin are in the purse​

Answer 1

Answer:

Step-by-step explanation:

$3.75 = 375cents

denomination = 5 cents and 2 cents

total no. of coins =33

let no. of 5 cent coins be a

let no. of 20 cent coins be 33 - a

amount of 5 cent coins = 5(a)

= 5a

amount of 20 cent coins = 20(33-a)

=660-20a

ATQ

=5a+660-20a = 375

=-15a=375-660

= a = -285 / -15

= a = 19

therefore no. of 5 cent coins is 19 and no. of 33 cent coins is 14.