Question

a purse contains a number of Rs 1 Rs 2 Rs 5 coins as given below :
If from the purse a coin is taken out at random, then find the probability that the coin :
A) is not a Rs 1 coin
B) is a Rs 3

Answer 1

A purse contains Rs1 , Rs2 and Rs5 coins.
No.of Rs1 coin in purse=10

No.of Rs2 coin in purse=14

No.of Rs5 coin in purse=14

No.of Rs2 and Rs5 coin in purse=14+14=28

No.of Rs3 coin in purse=0

Total coins=38
(a)
P(E)=No.of favourable outcomes/total no.of outcomes

P(not Rs1 coin)= no.of Rs2 and Rs5 coins/total no.of coins

P(not Rs1 coin)=28/38

Hence P(not Rs 1 coin)=14/19

(b)
P(Rs3 coin)=no.of Rs3 coin/total no.of coins

P(Rs3 coin)=0/38

P(Rs3 coin)=0

Hence P(Rs3) coin=0

Answer 2

Answer:

Hope it helps!

Step-by-step explanation:

A purse contains Rs1 , Rs2 and Rs5 coins.

No.of Rs1 coin in purse=10

No.of Rs2 coin in purse=14

No.of Rs5 coin in purse=14

No.of Rs2 and Rs5 coin in purse=14+14=28

No.of Rs3 coin in purse=0

Total coins=38

(a)

P(E)=No.of favourable outcomes/total no.of outcomes

P(not Rs1 coin)= no.of Rs2 and Rs5 coins/total no.of coins

P(not Rs1 coin)=28/38

Hence P(not Rs 1 coin)=14/19

(b)

P(Rs3 coin)=no.of Rs3 coin/total no.of coins

P(Rs3 coin)=0/38

P(Rs3 coin)=0

Hence P(Rs3) coin=0