a purse contains coins of 2 rupees,1rupees, 50paise and 25 paise in the ratio 1:2:4:8 If the total amount is 600 ,then the number of 25 paise coins exceeding those of 50 paise coin is
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let hcf=x
no of coins =x+2x+4x+8x
total value=2x+2x×1+0.5×4x+0.25×8x=600
4x+4x=600
x=600÷8
x=85
no of 25paise coin= 8×85
no of 50p coins= 4×85
no of exceeding coins=85(8-4)=85×4=340
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