a purse contains rs 250 in notes of denominations of 10 and 50. If the number of 10 rupees notes is one more than that of 50 rupees notes find the number of notes of each denomination. Please give me answer plzz
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Answered by
77
suppose the no. of 50 rs. notes = x
so the no. of 10 rs. coins = x+1
value of 50 rs. notes = 50x
value of 10 rs. notes =10(x+1)=10x+10
50x+10x+10 = 250
60x+10 = 250
60x = 250-10
60x = 240
x = 4
so the no. of 50 rs. notes = 4
and the no. of 10 rs. notes = 4+1=5
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so the no. of 10 rs. coins = x+1
value of 50 rs. notes = 50x
value of 10 rs. notes =10(x+1)=10x+10
50x+10x+10 = 250
60x+10 = 250
60x = 250-10
60x = 240
x = 4
so the no. of 50 rs. notes = 4
and the no. of 10 rs. notes = 4+1=5
hope it will help you
mark me as brainliest plzzz
Answered by
5
Answer:
Total number of notes in purse =10+20+30+40= 100
Therefore, total number of elementary events = 100
The note will not be a 500 rupee note :
There are 20+30+40 = 90 notes other than 500 rupee note
Therefore, favourable number of elementary events = 90
Hence, P(falling out of note other than 500 note) :
100
90
=
10
9
Step-by-step explanation:
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