Question

A purse contains rs.550 in notes of denominations of rs.10 and rs.50. If the number of rs.50 notes is one less than that of rs.10 notes, then find the number of rs.50 noted, guys this problem should be in linear equation.

Answer 1

No. of 10 rupee note =x
No. of 50 rupee note = x -1 ( according to question)

Now,
Total money 10 rupee = 10xx
Total money from 50 rupee = 50x–50
10x+50x–50=550
60x=600
X=10
No of 10/rupee note = 10
No. Of 50 rupee note= 10-1=9

Answer 2

Hi friend!

Here is your Answer
_____________________________

Let the number of 10Rs be X
then
number of 50rs be (x-1)

so
10 rs note = 10x
50 Rs note = 50(x-1)
=50x-50

Now equation

10x +50x -50 = 550
60x -50 = 550


60x = 550+50
X = 600/60
X = 10

Thus the 10 rs note are 10
&
50Rs note (10-1) = 9

50Rs note =9
10Rs note = 10

Hope it's helpful ✌✌