a purse contains Rs 550 in notes of denominators of rupees 10 and rupees 50 if the number of rupees 50 notes is one less than that of rupees 10, notes then find the number of 50 note.
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11
Answer:
Total amount in a purse= 550
Let number of notes of 10 =x
The number of notes of 50= x-1
According to the condition,
x×10+(x−1)×50=550
⟹10x+50x−50=550
⟹60x=550+50=600
⟹x=10
50 rupees notes= 10-1= 9
Answered by
1
Step-by-step explanation:
since total money us 550
let 50 notes by x and 10 notes be y
y=x+1
50x+10y=550
50x+10(x+1)=550
50x+10x+10=550
60x=540
×=9
y=10
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