a purse contains rupee 5000in notes of denominations of rupees 100 and 500 .if the total number of notes is 30 find the number of notes in each denominations
Answers
Answered by
5
Answer:
Step-by-step explanation:
Let number of rs.500 coins=x
Then number of rs.100 coins =30-x
Value of rs.500 coins= rs.500x
Value of rs.100 coins=rs.100(30-x)
=3000-100x
Apq.
500x+3000-100x=5000
400x=5000-3000
x=2000/400=5
No. of 500 coins=5
No. of 100 coins=30-x=30-5= 25
Answered by
7
Hey....!!!
Let the no. of Rs 100 notes be x
Therefore, no. of Rs 500 notes = 30 - x
Total amount = 100x + 500(30-x)
. = 100x + 15000 - 500x
. = 15000 - 400x
According to the question,
15000 - 400x = 5000
=> - 400x = 5000 - 15000
=> - 400x = - 10000
=> x = - 10000/-400
=> x = 25
So,
No. of Rs 100 notes = 25
No. of Rs 500 notes = 30 - 25 = 5
Hope it helps...!!!
Let the no. of Rs 100 notes be x
Therefore, no. of Rs 500 notes = 30 - x
Total amount = 100x + 500(30-x)
. = 100x + 15000 - 500x
. = 15000 - 400x
According to the question,
15000 - 400x = 5000
=> - 400x = 5000 - 15000
=> - 400x = - 10000
=> x = - 10000/-400
=> x = 25
So,
No. of Rs 100 notes = 25
No. of Rs 500 notes = 30 - 25 = 5
Hope it helps...!!!
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