Math, asked by saptarshisaha2007, 4 months ago

A purse contains some coins. Of these, the number of 1 rupee coins is 3 times the number of 5 rupee coins and twice the number of 2 rupee coins. If the total number of coins is 66, find the value of 5 rupee coins.

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Answers

Answered by padamataullaas
1

Answer:

let o, t, f be the number of  coins of 1, 2 & 5 denomoinations

Given,

o = 3f = 2t

o + t + f = 66

solving, for f

3f + 3f/2 + f = 66

f = 12

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Answered by riddhipalresha07
0

Answer:

value of 5 rupees coins=165 rupees

Step-by-step explanation:

let the no of 1 rupee coins be x

let the no of 5 rupee coins be 3x

let the no of 2 rupee coins be 2x

total = 66

x+3x+2x=66

6x=66

x=11

1 rupee coins=x=11=11 rupees

5 rupee coins=3x=33=165 rupees

2 rupee coins=2x=22=44 rupees

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