A pushing force of 15 newton act on a block at angle 30 degree original original vertical component force will be
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Explanation:
- let d2=145square+125square-2x145×cos(120') d=234.04N use sine rule 0=sine-1(125×sin 120 degree by 234.04=27.55 degree the 3rd force has magnitude234.04 N acting in the direction 27.55 degree T
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Answer:
7.5N
Explanation:
F=15N (given)
°=30°
vertical component of force is given as: Fsin °
=15×1/2
=7.5N
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