Question

A pushing force of 50 N acts on a block at angle of 30 with horizontal.The respective horizontal and vertical components of force will be

Answer 1

Answer:

a pushing force of 50 N acts

Explanation:

the angle of horizontal

Answer 2

Answer:

horizontal force = 43.30 N

vertical force = 25 N

Explanation:

Given,

Net force on the block,F = 50 N

angle made by the force with horizontal = 30°

So, the horizontal component of force can be given by

$F_h\ =\ F.cos\theta$

       $=\ 50\times cos30^o$

       $=50\times \dfrac{\sqrt{3}}{2}$

         = 43.30 N

So, the horizontal component of force will be 43.30 N

$F_v\ =\ F.sin\theta$

       $=\ 50\times sin30^o$

        $=\ 50\times \dfrac{1}{2}$

        = 25 N

The vertical component of force will be 25 N.