a puzzle?????.....no!!!!!a problem.......
a massive ball moving with a speed v collides head on with a fine ball having mass very much smaller than the mass of first ball at rest.the collision is elastic and then immediately after the impact the second ball will move with a speed approx equal to???
use formula v2=2m1/m1+m2*ui+2m2/m1+m2*u2
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we apply the conservation of linear momentum and also the conservation of kinetic energy principle. The collision is completely elastic so there is no loss of energy here.
let m1 > m2. u1 = v u2 = 0 and v1 and v2 are the speeds after collision.
The balls are colliding head on, so the velocities are all along one axis/straight line.
m1 v + 0 = m1 v1 + m2 v2 --- (1)
=> m1 (v - v1) = m2 v2 --- (2)
1/2 * m1 * v² + 0 = 1/2 * m1 * v1² + 1/2 * m2 * v2²
=> m1 * v² = m1 * v1² + m2 * v2² -- (3)
=> m1 (v² - v1²) = m2 * v2² --- (4)
Divide (4) by (2): Let v ≠ v1
v + v1 = v2
substituting this in equation (2), we get:
m1 (v - v1) = m2 (v + v1)
v1 = (m1 - m2) v / (m1 +m2) --- (5)
v2 = 2 m1 v /(m1 + m2) -- (6)
let m1 > m2. u1 = v u2 = 0 and v1 and v2 are the speeds after collision.
The balls are colliding head on, so the velocities are all along one axis/straight line.
m1 v + 0 = m1 v1 + m2 v2 --- (1)
=> m1 (v - v1) = m2 v2 --- (2)
1/2 * m1 * v² + 0 = 1/2 * m1 * v1² + 1/2 * m2 * v2²
=> m1 * v² = m1 * v1² + m2 * v2² -- (3)
=> m1 (v² - v1²) = m2 * v2² --- (4)
Divide (4) by (2): Let v ≠ v1
v + v1 = v2
substituting this in equation (2), we get:
m1 (v - v1) = m2 (v + v1)
v1 = (m1 - m2) v / (m1 +m2) --- (5)
v2 = 2 m1 v /(m1 + m2) -- (6)
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