a pyramid has a right angled triangular base and a volume of 160 m³. the lengths of the two shorter sides of the triangular base are 12m and 5m. find the height of the pyramid
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Given : a pyramid has a right angled triangular base and a volume of 160 m³. the lengths of the two shorter sides of the triangular base are 12m and 5m
To Find : height of the pyramid
Solution:
Volume of Pyramid = (1/3) Bh
B = Area of Base Triangle
h = Height of Pyramid
Area of Base Triangle = (1/2) * 12 * 5
= 30 m²
Volume of Pyramid = (1/3) Bh
= (1/3)* 30 * h
= 10 h m³
Volume of Pyramid = 160 m³ given
=> 10 h = 160
=> h = 16
height of the pyramid = 16 m
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