Question

A pyramid has a square base measuring 10 inches on each side. It has four faces that are congruent isosceles triangles. The height of each triangle is 13 inches. Find the surface area of the pyramid.

Answer 1

There are four triangles each having an area = bh/2 = (10*13)/(2) in2

So......(4)(10*13)/2 in2   = 260 in2

And the area of the base = 102   = 100in2

So...the total surface area =  [ 260 + 100]in2 = 360 in2