A pyramid on a square base has four equilateral triangles on its four equilateral triangles on its four other faces, each edges being 10 m. find its volume.
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V = 1/3 x b² x h
h² = hyponetuse² - 1/2 x b²
h² = 10² - 5²
= 100 - 25
= 75
h = √75
volume = 1/3 x 10² x √75
= 288.67 m³
h² = hyponetuse² - 1/2 x b²
h² = 10² - 5²
= 100 - 25
= 75
h = √75
volume = 1/3 x 10² x √75
= 288.67 m³
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