a Pythagorean triplet whose one member is 6
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let 6=m
2m= 2×6=12
m^2+1=6^2+1=36+1=37
m^2-1=6^2-1=36-1=35
therefore 12 , 37 , 35
2m= 2×6=12
m^2+1=6^2+1=36+1=37
m^2-1=6^2-1=36-1=35
therefore 12 , 37 , 35
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