Question

a quad bike travels 22 km south , 12 km west , 14 km in north in 30 min .
what is the average speed , average velocity and displacement of the quad bike.
note: root of 13 = 3.6

Answer 1

Answer:

96 km/h

The average speed can be calculated as the ratio between the total distance covered and the time taken:

where:

- the total distance is the total length of the path covered, regardless of the direction, so:

d = 22 km + 12 km + 14 km = 48 km

- total time:

t = 0.5 h

So, the average speed is

b) 14.4 km, at 33.7 degrees south of west

To find the displacement, we have to compute the net displacements along the two directions (north-south and east-west)

North-south direction (taking north as positive and south as negative):

(south)

East-west direction (taking east as positive):

(west)

So the net displacement is given by Pythagorean's theorem:

And the direction is given by

And the direction is south-west, so this is 33.7 degrees south of west

c) 28.8 km/h at 33.7 degrees south of west

The average velocity is the ratio between the net displacement and the time taken:

where we have:

displacement: d = 14.4 km

time taken: t = 0.5 h

So, the average velocity is

And the direction is the same as the displacement.

Answer 2

Please refer this photo.