A quadrantal triangle ABC, b= 78°14’, c = 49°8’ and a = 90°? What is the measure of angle A?
Answers
Answer:
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Step-by-step explanation:
What is the measure of angle p,q,r in the parallelogram A quadrantal triangle ABC, b= 78°14’, c = 49°8’ and a = 90°? What is the measure of angle A? given below
Step-by-step explanation:
Given:-
A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.
To find:-
Time taken to become velocity 80 m/s.
Equation Used:-
{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}
FirstEquationofMotion:v=u+at
Here,
v = Final Velocity
u = Initial Velocity
a = Acceleration
t = Time taken
Solution:-
Using first equation of motion,
\sf :\implies\:v=u+at:⟹v=u+at
Here,
v = 80 m/s
u = 20 m/s
a = 4 m/s²
Putting values,
\sf :\implies\:80=20+4t:⟹80=20+4t
\sf :\implies\:4t=80-20:⟹4t=80−20
\sf :\implies\:4t=60:⟹4t=60
\sf :\implies\:t=\dfrac{60}{4}:⟹t=
4
60
\sf :\implies\:t=15\:sec:⟹t=15sec
Hence, It will take 15 sec to become velocity 80 m/s.
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Step-by-step explanation:
Given:-
A body is moving with a speed of 20 m/s. When a certain force is applied, an acceleration of 4 m/s² is produced.
To find:-
Time taken to become velocity 80 m/s.
Equation Used:-
{\boxed{\bf{First\: Equation\:of\:Motion:v=u+at}}}
FirstEquationofMotion:v=u+at
Here,
v = Final Velocity
u = Initial Velocity
a = Acceleration
t = Time taken
Solution:-
Using first equation of motion,
\sf :\implies\:v=u+at:⟹v=u+at
Here,
v = 80 m/s
u = 20 m/s
a = 4 m/s²
Putting values,
\sf :\implies\:80=20+4t:⟹80=20+4t
\sf :\implies\:4t=80-20:⟹4t=80−20
\sf :\implies\:4t=60:⟹4t=60
\sf :\implies\:t=\dfrac{60}{4}:⟹t=
4
60
\sf :\implies\:t=15\:sec:⟹t=15sec
Hence, It will take 15 sec to become velocity 80 m/s.
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