Question

a quadratic equation ax2+bx+c=0 has real and equal root's,if​

Answer 1

Answer:If the quadratic equation ax2+bx+c=0,a>0 has real roots of opposite sign in the interval (-2,2), then prove that 1+c4a-|b2a|>0.

Step-by-step explanation:Follow me

Answer 2

Step-by-step explanation:

Theoritically the book says:

According to quadratic formula :

Roots of a quadratic equation ax2+bx+c=0 is given by:

x = (-b) +- [√(b^2-4ac)] / 2a

If you want real and equal roots then this

[√(b^2-4ac)] = √D also known as discriminant must be 0.

then, value of x is given by:

:x = (-b) / 2a

Hence your both roots are rational numbers or real and equal to (-b/2a).

This was theory part.

Objectively,

when you are asked about real and equal roots it means the graph of quadratic equation touches the x axis at just 1 point. It's that simple.

So, a quadratic equation ax2+bx+c=0 has real and equal roots if ,

#1. Discriminant (D) is 0. * D = (b^2-4ac)

#2. Value of x is only -b/2a

#3. Graph of quadratic equation touches the x axis at just 1 point.

Any one of these you can pick as your answer.

Thats entire concept of real and equal roots covered up. Hope it helps :)