Math, asked by fatima6668, 1 year ago

a quadratic equation whose one root is 3 +√2 is​

Answers

Answered by rahul72799
112

Answer:

x^2 - 6x +7=0.

is the required equation

Step-by-step explanation:

i have given steps in image.

hope it is helpful..

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Attachments:

fatima6668: nhi ye answer nhi u
rahul72799: then other roots ka equation btana h??
fatima6668: nhi usi ka
fatima6668: koi baat nhi
rahul72799: ab sahi h??
fatima6668: hmm
rahul72799: plz mark it brainliest
rahul72799: thanks
Answered by pulakmath007
37

The quadratic equation whose one root is 3 + √2 is x² - 6x + 7 = 0

Given :

One root of quadratic equation is 3 + √2

To find :

The quadratic equation

Solution :

Step 1 of 2 :

Write down the root of the equation

Here it is given that one root of quadratic equation is 3 + √2

Step 2 of 2 :

Find the equation

Let x be the variable involved

Then we have

\displaystyle \sf{  x = 3 +  \sqrt{2} }

\displaystyle \sf{ \implies x  - 3  =  \sqrt{2} }

\displaystyle \sf{ \implies {(x  - 3 )}^{2}   =  {(\sqrt{2} )}^{2} }

\displaystyle \sf{ \implies  {x}^{2} - 6x + 9 = 2  }

\displaystyle \sf{ \implies  {x}^{2} - 6x + 9  - 2  = 0 }

\displaystyle \sf{ \implies  {x}^{2} - 6x + 7  = 0 }

Hence the required Quadratic equation is x² - 6x + 7 = 0

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