Question

a quadratic equation whose one zero is 5 and product of zeroes is 0 is

Answer 1

Answer:

x2 -5x +0

x2 -5x

is the answer of this question

Answer 2

The quadratic equation is $x^{2} - 5x = 0$.

Step-by-step explanation:

Let the quadratic equation, $ax^{2} + bx + c = 0$.................(i)

Let one zero = p = 5 (Given), another zero = q

Sum of the zeros = $\frac{-b}{a}$

=> p + q = $\frac{-b}{a}$

=> 5 + q = $\frac{-b}{a}$................(ii)

Product of zeroes = $\frac{c}{a}$ = 0 (Given) => c = 0

=>  pq = 0

=> p = 5

So, q must be 0. => q = 0

Plug the value of q in equation(ii),

=> 5 + 0 = $\frac{-b}{a}$

=> $\frac{-b}{a} = 5$

=> b = -5a

If a = 1 then b = -5 x 1 = -5

Plug the value of a, b and c in equation(i),

$(1)x^{2} +(-5)x + 0 = 0\\=> x^{2} - 5x = 0$

Hence, the quadratic equation is $x^{2} - 5x = 0$.