Question

A quadratic holynomial the sum of whose zeroes is 0 and their
product is -9​

Answer 1

Answer:

hope it will help you:-)

Answer 2

ax^+bx+c=k(x^-(a+b)x+(ab) )

(a+b)=0

(ab)=-9

=k(x^-(0)x+(-9))

=k(x^-0x-9)

put k=1

=1(k(x^-0x-9)

=x^-0x-9