Question

A quadratic polynomial having -2 and 4 is

Answer 1

Answer:

hi I hope u understand

Step-by-step explanation:

xsquare + 2x-8

Answer 2

$\huge{\boxed{\bf{\red{Answer:-}}}}$

$\sf\underline{\blue{Given}}$

$\:\bullet let \:\alpha=(-2)\\ \\ \sf\:\:\:\bullet and\: \beta=4$

$\sf \bullet sum\:of\:zero's(\alpha+\beta)=(-2)+4= 2\\ \\ \sf\bullet product\:of\:zero's(\alpha\beta)=(-2)\times 4= (-8)$

By Quadratic polynomial

$\bigstar{\boxed{\sf{ax{}^{2}+bx+c}}}$

$\bigstar{\boxed{\sf{ x{}^{2}-(sum\:of\: zero's)x+(product\:of\: zero's)}}}$

$\sf\implies k(x{}^{2}-(\alpha+\beta)x+\alpha\beta)=0\\ \\ \sf\implies k(x{}^{2}-2x-8)=0\\ \\ \sf\implies k(x{}^{2}-2x-8)=0\\ \\ \sf\: \:\:let\:\:k=1\\ \\ \sf\implies x{}^{2}-2x-8=\dfrac{0}{1}\\ \\ \sf\implies x{}^{2}-2x-8=0\\ \\ \sf\implies {\purple{x{}^{2}-2x-8=0}}$

$\boxed{\sf{\therefore One\: equation=x{}^{2}-2x-8}}$