Question

A quadratic polynomial, the sum and product of whose zeroes are -3 and -4, respectively,

Answer 1

Step-by-step explanation:

-b/a = -3

c/a = -4

now let a be 2

so b should be 6

and c should be -8

hence the equation could be:

2x^2 + 3x -8

Answer 2

Answer: k (x² + 3x + 12)

Solution:

Given:

• The sum of zeroes of a quadratic polynomial  = -3 = (∝ + β)
• The product zeroes of a quadratic polynomial = -4 = (∝β)

To find:

The quadratic polynomial.

Proof:

According to the question, the quadratic polynomial by formula

= k [ x² - (Sum of the zeroes)x + Product of the zeroes ]

(where k is a constant)

= k [ x² -  (∝ + β)x + ∝β ]

= k [x² - (-3)x + (-3)(-4)]

= k (x² + 3x + 12)

The quadratic polynomial the sum and product of whose zeroes are respectively -3 and -4 = k (x² + 3x + 12)

Hope you understood.

Thank You.