Question

A quadratic polynomial whise zeris are 2 and -3

Answer 1

Answer:

${x}^{2} + x - 6 = 0.$

Step-by-step explanation:

$\alpha + \beta = 2 - 3 = - 1 \\ \\ \alpha \beta = 2 \times - 3 = - 6 \\ \\ {x}^{2} - ( \alpha + \beta )x + \alpha \beta = 0 \\ \\ {x}^{2} + x - 6 = 0.$