a quadratic polynomial whose 1 zero is 6 and sum of zeros is zero is
Answers
Answered by
1
Answer:
let the roots be a and b
Step-by-step explanation:
GIVEN a=6
a+b=0
6+b=0
b=-6
a×b=6×-6=-36
we know that ...
x^2-(a+b)x+ab=0
x^2-(0)x+(-36)=0
x^2-36=0...
HOPE IT HELPS YOU..
Answered by
1
Step-by-step explanation:
alpha +beta =0 (given)
alpha +6=0
alpha = -6
alpha(beta) =6 (-6)
alpha(beta)= -36
therefore
x2 -(alpha+beta)x +[alpha(beta)] = x2 -36
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